Aligning data that must be preserved to the correct tier of storage until it is no longer useful is anexample of：（）

A、Business Continuity

B、Disaster Recovery Plan

C、Storage Consolidation

D、Information Lifecycle Management

获得稳定的工作职位是马期洛需求金字塔理论中（）的一个例子。

A、安全需求

B、自我价值实现

C、物质需求

D、归属感

Which parameters are valid SCREEN options for combating operating system probes?（）

A、syn-fin, syn-flood, and tcp-no-frag

B、syn-fin, port-scan, and tcp-no-flag

C、syn-fin, fin-no-ack, and tcp-no-frag

D、syn-fin, syn-ack-ack-proxy, and tcp-no-frag

You have enabled the Slow Query Log for a short period. When you process the Slow Query Log, you receive the following snip of output: Count: 100 Time=0 .22a (22s) Lock=0.00s (0s) Rows=0.0 (0), root[root] @localhost CREATE TABLE 't1' (id serial,id0 varchar(N) unique key,intcaoll INT (N) ,intco12 INT(N) ,intco13 INT(N) ,intco14 INT(N) ,intco15 INT(N) ,charcol1 VARVHAR(N) ,charcol2 VARCHAR(N) charcol3 VARCHAR (N) ,charcol4 VARVHAR(N) ,charcol5 VARCHAR(N) charcol6 VARCHAR (N) ,charcol7 VARVHAR(N) ,charcol8 VARCHAR(N) charcol9 VARCHAR (N) .charcol 10 VACHAR (N) ) Count: 64000 Time-0.02s (1213s) Lock=0.00s (6s) Rows=1.0 (64000), root [root]@ localhost SELECT intocl1, intco12, intco13, intco14, intco15, intco16,intco17, intco18 ,intcol9, intcol10, charcol1, charcol2, charcol3, charcol4, charcol5, charcol6 ,charcol7, charcol8, charcol9, charcol10 FROM t1 WHERE id = 's' Count: 1 Time=0.02s (0s) Lock=0.00s (0s) Rows=1.0 (1) agent [agent] @localhost SELECT Select_priv, Repl_client_priv, Show_db_priv, Super_priv, Process_priv FROM mysql.user WHERE CONCAT (user, 's', host) = CURRENT_USER （　） Count: 48000 Time=0.02s (778s) Lock=0.00 (3s) Rows=1.0 (48000), root[root]@localhost SELECT intocl1,intcol2,intcol3, intcol4, intcol5, charcol1, charcol2, charcol3 ,charcol4, charcol5, charcol6, charcol7, charcol8, charcol9, charcol10 FROM t1 WHERE id = 's' You want to tune the query such that it provides the greatest overall time savings. Which query will accomplish this?（）

A、CHEATE TABLE 't1' (id serial, id0 varchar (N) unique key, intcol1 INT (N) ,intcol2 INT (N), intcol3 INT(N) ,intcol4 INT(N), intcol5 INT(N), charool1 VARCHAR (N) ,charcol2 VARCHAR (N), charcol3 VARCHAR(N), charcol4 VARCHAR(N), charcol5 VARCHAR (N) ,charcol6 VARCHAR (N), charcol7 VARCHAR(N), charcol8 VARCHAR(N), charcol9 VARCHAR (N) ,charcol10 VARCHAR (N)

B、SELECT intcol1, intcol2, intcol3, intcol4, intcol5, intcol6, intcol7, intcol8, intcol9, Intcol10, intcol11, intcol12, intcol13, intcol14, intcol15, intcol16, intcol17, intcol18, intcol19, charcol10 FROM t1 WHERE id = 's'

C、SELECT Select_priv, Repl_client_priv, Show_db_priv, Super_priv, Process_priv FROM mysql.user WHERE CONCAT (user,'s', host) = CURRENT_USER()

D、SELECT intcol1, intcol2, intcol3, intcol4, intcol5, charcol1, charcol2, charcol3, charcol4, charcol5, charcol6, charcol7, charcol8, charcol9, charcol10 FROM t1 WHERE id = 's'

你在一个狭小的办公室内召集几个项目干系人及客户开会。他们正进行激烈的争吵，人们相互大吵大闹。每个人都很生气并对处理项目的最佳方法意见严重不统一。作为项目经理，你的任务是在满足竞争需要和目标时，尽量平衡项目干系人的利益。总的来说，项目干系人之间争端的解决应该有利于（）。

A、发起人

B、高层经理

C、运行中的机构

D、客户

基站标配发货之后，如果基站需要大底座，则需要（）流程。